3u^2-7u-4=0

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Solution for 3u^2-7u-4=0 equation: 



3u^2-7u-4=0

a = 3; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·3·(-4)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{97}}{2*3}=\frac{7-\sqrt{97}}{6}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{97}}{2*3}=\frac{7+\sqrt{97}}{6}
$

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